←Vrati se na zadatke1. ZadatakIzračunaj (962:122−(−2)2):3⋅23+1.\left(96^2:12^2-(-2)^2\right):\sqrt{3\cdot2^3+1}.(962:122−(−2)2):3⋅23+1.RješenjeVrijedi 962:122=(96:12)2=82=6496^2:12^2=(96:12)^2=8^2=64962:122=(96:12)2=82=64. Stoga je 962:122−(−2)2=64−4=6096^2:12^2-(-2)^2=64-4=60962:122−(−2)2=64−4=60. Također vrijedi 3⋅23+1=3⋅8+1=25=5\sqrt{3\cdot2^3+1}=\sqrt{3\cdot8+1}=\sqrt{25}=53⋅23+1=3⋅8+1=25=5. Konačno, slijedi (962:122−(−2)2):3⋅23+1=60:5=12.\left(96^2:12^2-(-2)^2\right):\sqrt{3\cdot2^3+1}=60:5=12.(962:122−(−2)2):3⋅23+1=60:5=12.
