←Vrati se na zadatke2. ZadatakIzračunajte 1−1x21+6x+5x2⋅x+5x−1.\frac{1-\frac1{x^2}}{1+\frac6x+\frac5{x^2}}\cdot\frac{x+5}{x-1}.1+x6+x251−x21⋅x−1x+5.Prikaži rješenjeRješenje1−1x21+6x+5x2⋅x+5x−1=x2−1x2x2+6x+5x2⋅x+5x−1==(x−1)⋅(x+1)(x+1)⋅(x+5)⋅x+5x−1=1\begin{aligned} \frac{1-\frac1{x^2}}{1+\frac6x+\frac5{x^2}}\cdot\frac{x+5}{x-1} &=\frac{\frac{x^2-1}{x^2}}{\frac{x^2+6x+5}{x^2}}\cdot\frac{x+5}{x-1}=\\ &=\frac{(x-1)\cdot(x+1)}{(x+1)\cdot(x+5)}\cdot\frac{x+5}{x-1}=1 \end{aligned}1+x6+x251−x21⋅x−1x+5=x2x2+6x+5x2x2−1⋅x−1x+5==(x+1)⋅(x+5)(x−1)⋅(x+1)⋅x−1x+5=1 x≠1,0,−1,−5x\ne1,0,-1,-5x=1,0,−1,−5Pomakni formulu lijevo ili desno.