←Vrati se na zadatke1. ZadatakSkrati razlomak (2n−1+1)2−4n−14n+2n+1+1\dfrac{(2^{n-1}+1)^2-4^{n-1}}{4^n+2^{n+1}+1}4n+2n+1+1(2n−1+1)2−4n−1.Prikaži rješenjeRješenje(2n−1+1)2−4n−14n+2n+1+1=4n−1+2⋅2n−1+1−4n−14n+2⋅2n+1=2n+1(2n+1)2=12n+1\begin{aligned} \frac{(2^{n-1}+1)^2-4^{n-1}}{4^n+2^{n+1}+1} &=\frac{4^{n-1}+2\cdot2^{n-1}+1-4^{n-1}}{4^n+2\cdot2^n+1}\\ &=\frac{2^n+1}{(2^n+1)^2}=\frac1{2^n+1} \end{aligned}4n+2n+1+1(2n−1+1)2−4n−1=4n+2⋅2n+14n−1+2⋅2n−1+1−4n−1=(2n+1)22n+1=2n+11Pomakni formulu lijevo ili desno.