←Vrati se na zadatke1. ZadatakKoliko je puta vrijednost izraza 2⋅723:(223+0.5:112)(213−119⋅0.75):7132\cdot\frac{7\frac{2}{3}:\left(2\frac{2}{3}+0.5:1\frac{1}{2}\right)}{\left(2\frac{1}{3}-1\frac{1}{9}\cdot0.75\right):7\frac{1}{3}}2⋅(231−191⋅0.75):731732:(232+0.5:121) manja od broja 202420242024?RješenjeVrijednost zadanog izraza je: 2⋅723:(223+0.5:112)(213−119⋅0.75):713=2⋅233:(83+12:32)(73−109⋅34):223=2⋅233:(83+13)(73−56):223=2⋅233:396:223=2⋅239:944=202481.\begin{aligned} 2\cdot\frac{7\frac{2}{3}:\left(2\frac{2}{3}+0.5:1\frac{1}{2}\right)}{\left(2\frac{1}{3}-1\frac{1}{9}\cdot0.75\right):7\frac{1}{3}} &=2\cdot\frac{\frac{23}{3}:\left(\frac{8}{3}+\frac{1}{2}:\frac{3}{2}\right)}{\left(\frac{7}{3}-\frac{10}{9}\cdot\frac{3}{4}\right):\frac{22}{3}}\\ &=2\cdot\frac{\frac{23}{3}:\left(\frac{8}{3}+\frac{1}{3}\right)}{\left(\frac{7}{3}-\frac{5}{6}\right):\frac{22}{3}}\\ &=2\cdot\frac{\frac{23}{3}:3}{\frac{9}{6}:\frac{22}{3}}\\ &=2\cdot\frac{23}{9}:\frac{9}{44}\\ &=\frac{2024}{81}. \end{aligned}2⋅(231−191⋅0.75):731732:(232+0.5:121)=2⋅(37−910⋅43):322323:(38+21:23)=2⋅(37−65):322323:(38+31)=2⋅69:322323:3=2⋅923:449=812024. Zadani izraz je 818181 puta manji od broja 202420242024.
