←Vrati se na zadatke1. ZadatakRiješi jednadžbu: 8x+133=19−12x2−(16x−7−4x6).\frac{8x+13}{3}=\frac{19-12x}{2}-\left(16x-\frac{7-4x}{6}\right).38x+13=219−12x−(16x−67−4x).Rješenje8x+133=19−12x2−16x+7−4x6/⋅6\frac{8x+13}{3}=\frac{19-12x}{2}-16x+\frac{7-4x}{6}\quad /\cdot 638x+13=219−12x−16x+67−4x/⋅6 2⋅(8x+13)=3⋅(19−12x)−96x+7−4x2\cdot(8x+13)=3\cdot(19-12x)-96x+7-4x2⋅(8x+13)=3⋅(19−12x)−96x+7−4x 16x+26=57−36x−96x+7−4x16x+26=57-36x-96x+7-4x16x+26=57−36x−96x+7−4x 16x+36x+96x+4x=57+7−2616x+36x+96x+4x=57+7-2616x+36x+96x+4x=57+7−26 152x=38/:152152x=38\quad /:152152x=38/:152 x=38152x=\frac{38}{152}x=15238 x=14x=\frac{1}{4}x=41
