←Vrati se na zadatke1. ZadatakAko je ab−a=ba+b\frac ab-a=\frac ba+bba−a=ab+b i a+b≠0a+b\ne0a+b=0, a≠0a\ne0a=0, b≠0b\ne0b=0, koliko je 1a−1b\frac1a-\frac1ba1−b1?Prikaži rješenjeRješenjeTransformirajmo zadanu jednakost: ab−ba=a+ba2−b2ab=a+b(a−b)(a+b)ab=a+b/ :(a+b)≠0a−bab=1aab−bab=11b−1a=11a−1b=−1\begin{aligned} \frac ab-\frac ba&=a+b\\ \frac{a^2-b^2}{ab}&=a+b\\ \frac{(a-b)(a+b)}{ab}&=a+b\quad/\;:(a+b)\ne0\\ \frac{a-b}{ab}&=1\\ \frac a{ab}-\frac b{ab}&=1\\ \frac1b-\frac1a&=1\\ \frac1a-\frac1b&=-1 \end{aligned}ba−ababa2−b2ab(a−b)(a+b)aba−baba−abbb1−a1a1−b1=a+b=a+b=a+b/:(a+b)=0=1=1=1=−1Pomakni formulu lijevo ili desno.