Izračunaj (2006−1+20081+2007⋅2005)2.
Rješenje
(2006−1+20081+2007⋅2005)2=(2006−1+20081+(2006+1)(2006−1))2=(2006−1+20081+20062−12)2=(2006−1+200820062)2=(2006−1+2008⋅2006)2=(2006−1+(2007+1)(2007−1))2=(2006−1+20072−12)2=(2006−20072)2=(2006−2007)2=(−1)2=1