←Vrati se na zadatke1. ZadatakAko je a+5ba−5b=5,a≠0,b≠0,a≠5b,\frac{a+5b}{a-5b}=5,\qquad a\ne0,\quad b\ne0,\quad a\ne5b,a−5ba+5b=5,a=0,b=0,a=5b, koliko je a+2ba−2b?\frac{a+2b}{a-2b}?a−2ba+2b?Rješenjea+5ba−5b=5\frac{a+5b}{a-5b}=5a−5ba+5b=5 a+5b=5(a−5b)a+5b=5(a-5b)a+5b=5(a−5b) a+5b=5a−25ba+5b=5a-25ba+5b=5a−25b 4a=30b4a=30b4a=30b a=152ba=\frac{15}{2}ba=215b a+2ba−2b=152b+2b152b−2b=192b112b=1911.\frac{a+2b}{a-2b}=\frac{\frac{15}{2}b+2b}{\frac{15}{2}b-2b}=\frac{\frac{19}{2}b}{\frac{11}{2}b}=\frac{19}{11}.a−2ba+2b=215b−2b215b+2b=211b219b=1119.
