←Vrati se na zadatke1. ZadatakIzračunaj vrijednost izraza I=10+2⋅(x+1)2−x⋅(4−3x)I=10+2\cdot(x+1)^2-x\cdot(4-3x)I=10+2⋅(x+1)2−x⋅(4−3x), za x=−20x=-20x=−20.RješenjeI=10+2⋅(−20+1)2−(−20)⋅(4−3⋅(−20))=10+2⋅(−19)2−(−20)⋅(4+60)=10+2⋅361−(−20)⋅64=10+722+1280=2012.\begin{aligned} I&=10+2\cdot(-20+1)^2-(-20)\cdot(4-3\cdot(-20))\\ &=10+2\cdot(-19)^2-(-20)\cdot(4+60)\\ &=10+2\cdot361-(-20)\cdot64\\ &=10+722+1280\\ &=2012. \end{aligned}I=10+2⋅(−20+1)2−(−20)⋅(4−3⋅(−20))=10+2⋅(−19)2−(−20)⋅(4+60)=10+2⋅361−(−20)⋅64=10+722+1280=2012.
