←Vrati se na zadatke2. ZadatakAko je 9x2+4y2−12xy−16a2=129x^2+4y^2-12xy-16a^2=129x2+4y2−12xy−16a2=12 i 3x−2y+4a=43x-2y+4a=43x−2y+4a=4, koliko je 3x−2y3x-2y3x−2y?Prikaži rješenjeRješenje9x2+4y2−12xy−16a2=12(3x−2y)2−16a2=12(3x−2y−4a)(3x−2y+4a)=12(3x−2y−4a)⋅4=123x−2y−4a=33x−2y+4a=42(3x−2y)=73x−2y=72\begin{aligned} 9x^2+4y^2-12xy-16a^2&=12\\ (3x-2y)^2-16a^2&=12\\ (3x-2y-4a)(3x-2y+4a)&=12\\ (3x-2y-4a)\cdot4&=12\\ 3x-2y-4a&=3\\ 3x-2y+4a&=4\\ 2(3x-2y)&=7\\ 3x-2y&=\frac72 \end{aligned}9x2+4y2−12xy−16a2(3x−2y)2−16a2(3x−2y−4a)(3x−2y+4a)(3x−2y−4a)⋅43x−2y−4a3x−2y+4a2(3x−2y)3x−2y=12=12=12=12=3=4=7=27Pomakni formulu lijevo ili desno.
