←Vrati se na zadatke1. ZadatakRacionaliziraj nazivnik razlomka 335−3.\frac{3}{3\sqrt5-\sqrt3}.35−33.Rješenje335−3=335−3⋅35+335+3=3(35+3)(35)2−(3)2=3(35+3)9⋅5−3=3(35+3)42=35+314\begin{aligned} \frac{3}{3\sqrt5-\sqrt3} &=\frac{3}{3\sqrt5-\sqrt3}\cdot\frac{3\sqrt5+\sqrt3}{3\sqrt5+\sqrt3}\\ &=\frac{3(3\sqrt5+\sqrt3)}{(3\sqrt5)^2-(\sqrt3)^2}\\ &=\frac{3(3\sqrt5+\sqrt3)}{9\cdot5-3}\\ &=\frac{3(3\sqrt5+\sqrt3)}{42}\\ &=\frac{3\sqrt5+\sqrt3}{14} \end{aligned}35−33=35−33⋅35+335+3=(35)2−(3)23(35+3)=9⋅5−33(35+3)=423(35+3)=1435+3
