←Vrati se na zadatke1. ZadatakZa tri broja a, b i c vrijede razmjeri a:b=7:3a : b = 7 : 3a:b=7:3 i b:c=5:2b : c = 5 : 2b:c=5:2. Koliko će biti (a−b):(b+c)(a-b) : (b+c)(a−b):(b+c)?Prikaži rješenjeRješenjea=73b, b=52ca = \frac73 b,\ b = \frac52 ca=37b, b=25c a=73b=73⋅52c=356ca = \frac73 b = \frac73 \cdot \frac52 c = \frac{35}{6}ca=37b=37⋅25c=635c (a−b):(b+c)=(356c−52c):(52c+c)=(103c):(72c)=20:21\begin{aligned} (a-b):(b+c) &= \left(\frac{35}{6}c - \frac52 c\right):\left(\frac52 c+c\right) \\ &= \left(\frac{10}{3}c\right):\left(\frac72 c\right) = 20:21 \end{aligned}(a−b):(b+c)=(635c−25c):(25c+c)=(310c):(27c)=20:21Pomakni formulu lijevo ili desno.