2. Zadatak

Rastav broja $2012$ na proste faktore je $2012=2\cdot2\cdot503$.

Umnožak $2012$ dobijemo u sljedećim slučajevima:

a) $2$, $2$, $503$, $\underbrace{1,\ldots,1}_{1504}$,

b) $4$, $503$, $\underbrace{1,\ldots,1}_{1505}$,

c) $2$, $1006$, $\underbrace{1,\ldots,1}_{1505}$,

d) $2012$, $\underbrace{1,\ldots,1}_{1506}$.

Zbroj tih brojeva je: a) $2011$, b) $2012$, c) $2513$, d) $3518$.

Traženi brojevi su $4$, $503$, $\underbrace{1,\ldots,1}_{1505}$.