Dani su kvadrati A B C D ABCD A B C D i B E F G BEFG B E F G kao na slici, pri čemu je duljina stranice manjeg kvadrata 1 dm, a duljina stranice većeg kvadrata 20 cm. Izračunaj površinu trokuta △ D E G \triangle DEG △ D E G .
Prikaži rješenje Rješenje
P △ B E G = 10 ⋅ 10 2 = 50 cm 2 P_{\triangle BEG} = \frac{10 \cdot 10}{2} = 50\text{ cm}^2 P △ B E G = 2 10 ⋅ 10 = 50 cm 2
P □ A B G D = P □ A B C D − P △ C D G = 20 ⋅ 20 − 20 ⋅ 10 2 = 400 − 100 = 300 cm 2 \begin{aligned} P_{\square ABGD} &= P_{\square ABCD} - P_{\triangle CDG} = 20 \cdot 20 - \frac{20 \cdot 10}{2} \\ &= 400 - 100 = 300\text{ cm}^2 \end{aligned} P □ A B G D = P □ A B C D − P △ C D G = 20 ⋅ 20 − 2 20 ⋅ 10 = 400 − 100 = 300 cm 2
P △ A E D = 30 ⋅ 20 2 = 300 cm 2 P_{\triangle AED} = \frac{30 \cdot 20}{2} = 300\text{ cm}^2 P △ A E D = 2 30 ⋅ 20 = 300 cm 2
P △ D E G = ( P △ B E G + P □ A B G D ) − P △ A E D = ( 50 + 300 ) − 300 = 50 cm 2 \begin{aligned} P_{\triangle DEG} &= (P_{\triangle BEG} + P_{\square ABGD}) - P_{\triangle AED} \\ &= (50 + 300) - 300 = 50\text{ cm}^2 \end{aligned} P △ D E G = ( P △ B E G + P □ A B G D ) − P △ A E D = ( 50 + 300 ) − 300 = 50 cm 2
Površina trokuta △ D E G \triangle DEG △ D E G je 50 cm 2 50\text{ cm}^2 50 cm 2 .