2. Zadatak

Uz primjenu svojstva distributivnosti množenja prema zbrajanju odnosno distributivnosti množenja prema oduzimanju slijedi $$\begin{aligned}&5\cdot(31\cdot2\cdot44+38\cdot2\cdot22)+11\cdot(4\cdot117-17\cdot2\cdot2)\cdot4+11\cdot7\cdot(31\cdot2+2\cdot69)\\&=5\cdot(62\cdot44+38\cdot44)+11\cdot(4\cdot117-17\cdot4)\cdot4+11\cdot7\cdot2\cdot(31+69)\\&=5\cdot(62+38)\cdot44+11\cdot4\cdot(117-17)\cdot4+11\cdot7\cdot2\cdot100\\&=5\cdot100\cdot44+11\cdot16\cdot100+11\cdot14\cdot100\\&=5\cdot100\cdot44+11\cdot(16+14)\cdot100\\&=5\cdot100\cdot4\cdot11+11\cdot5\cdot6\cdot100\\&=5\cdot100\cdot11\cdot(4+6)\\&=55000\end{aligned}$$