←Vrati se na zadatke5. ZadatakZamijeni Δ\DeltaΔ brojem tako da vrijedi jednakost: 238+237+236+Δ+264+263+262=16⋅23+82⋅(35−19)−5⋅16.238+237+236+\Delta+264+263+262=16\cdot23+82\cdot(35-19)-5\cdot16.238+237+236+Δ+264+263+262=16⋅23+82⋅(35−19)−5⋅16.Rješenje238+262=500238+262=500238+262=500 237+263=500237+263=500237+263=500 236+264=500236+264=500236+264=500 Lijeva strana jednakosti je 1500+Δ1500+\Delta1500+Δ. Desna strana jednakosti: 16⋅23+82⋅(35−19)−5⋅16=16\cdot23+82\cdot(35-19)-5\cdot16=16⋅23+82⋅(35−19)−5⋅16= =16⋅23+82⋅16−5⋅16==16\cdot23+82\cdot16-5\cdot16==16⋅23+82⋅16−5⋅16= =16⋅(23+82−5)==16\cdot(23+82-5)==16⋅(23+82−5)= =16⋅100==16\cdot100==16⋅100= =1600=1600=1600 Na kraju, 1500+Δ=16001500+\Delta=16001500+Δ=1600 te je Δ=100\Delta=100Δ=100.
